You have to find the K value to figure out how much will be left after 16.35 days. To find that you use the decay formula which is P = Po * e^-k(t). Since we are doing half life we know P must be 1/2 and t is 2.69 days. So the equation is .5 = e^-k(2.69). Now just take the natural log of both sides and we get Ln(.5) = -k(2.69). From there we just divide out the 2.69 and end up with Ln(.5)/2.69 = -k. Your k value should be positive if you have -k equal to something negative. After that you put the k value into the original equation and put 16.35 in for t. That will be P = e^-k(16.35). Solve for P which is just algebra on the right side of the equation.
You have to find the K value to figure out how much will be left after 16.35 days. To find that you use the decay formula which is P = Po * e^-k(t). Since we are doing half life we know P must be 1/2 and t is 2.69 days. So the equation is .5 = e^-k(2.69). Now just take the natural log of both sides and we get Ln(.5) = -k(2.69). From there we just divide out the 2.69 and end up with Ln(.5)/2.69 = -k. Your k value should be positive if you have -k equal to something negative. After that you put the k value into the original equation and put 16.35 in for t. That will be P = e^-k(16.35). Solve for P which is just algebra on the right side of the equation.
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